Point O is the center of a circle passing through points A, B, and C. Which statement about ABC is true?
A) OA bisects A. B) OA bisects BC . C) OA is perpendicular to BC D) The perpendicular bisectors of AB , BC , and AC pass through O. E) The bisectors of AB, BC , and AC through O have equal lengths.
@IMStuck , could you help please?(:
I'm here!!! Do you have a picture of this? I'm losing the specifics of it trying to decipher the way it looks.
they didn't give me a picture. just the question and answers! this ones really hard!
Ok, then. Let me have a go at this! BRB!!
Ok, wow. I think I found it but it is kukoo. Here is what I have drawn. Bear with me.|dw:1402330166921:dw|
The segment tangent to the circle at each of the points creates a right angle. See that?
yes!
Radius OA definitely does not bisect BC, which is the second choice. So it's not that one. I skipped the first one on purpose.
ok(:
Can you have more than one answer that is correct here?
i don't think so!
|dw:1402330684558:dw|This is what results when you draw that. Look at my first drawing. ABC actually form a triangle. If this is correct, then OA does bisect A, if A is an angle. OA is also perpendicular to BC if this is a triangle. The perpendicular bisectors of AB, BC, AC do pass through the center because that is the definition of a perpendicular bisector (it passes through the center). And, because O is the center of the circle, hence the center of the triangle, all the radii that generate from O are equal in length. Hmm...
You definitely do not have an image for this? Left to my own devices, that is what I came up with and I am confused if there is not supposed to be more than one answer.
im just gonna take a good guess for this one, because nobody seems to know it! no worries! thank you so much for the help!!
I think if I had to make the best guess out of the given, I'd pick A. So sorry I couldn't be of more help to you!
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