Question

can someone help me with trig

Answer 1

the highlighted part hw it say 2pi ,hw am i suppose to find the result

Answer 2

hw to get that 150 degrees in astc

Answer 3

Your answer is correct.

Answer 4

i know it is but i dunno hw in answer they got 150

Answer 5

Ok, got it. I'll explain.

Answer 6

thank u

Answer 7

Let me draw the unit circle.

Answer 8

Notice that for an angle of 30 degrees, the y-coordinate of the point of intersection of the terminal ray of the 30-degree angle and the unit circle has a y-coordinate of 0.5.
This is how we know that the arcsin of 0.5 is 30 degrees.
This is what gives the answer of 30 degrees for this problem.
You follow so far?

Answer 9

yes

Answer 10

where did u get the 0.5 from?

Answer 11

You had in your equation gotten to:

\(\sin \theta = \dfrac{1}{2} \)

1/2 is the same as 0.5

Answer 12

its 30 degrees in this question because of \[\sin \theta =\frac{ 1 }{ \sqrt{2} }\]

Answer 13

ohk

Answer 14

No in your problem it is simply
\(\sin \theta = \dfrac{1}{2} \), and now we need theta.

Because \(\sin 30^o = 0.5\), that means \( \theta = 30^o\)

Answer 15

yes

Answer 16

Ok, so we have theta is 30 deg. Now how do we get 150 deg?

Answer 17

yes

Answer 18

You are looking for all answers in the interval
\(0 \lt \theta \lt 2 \pi\).

That interval in degrees is:
\(0 \lt \theta \lt 360^o\)

Ok?

Answer 19

yes

Answer 20

Now let's look again at the unit circle.