Solve the following system of equations. 3x + 3y + 2z = -5 x + y + 3z = -4 2x + 2y + 5z = -7 A. (-4, -3, 1) B. (-4, 3, -1) C. (4, -3, -1) D. (-4, -3, -1)
@Hero can you help me
@zepdrix
Umm have you learned about matrices? :o
Yes although I struggled with it but I have learned it. @zepdrix
You could write the system as a matrix and try to get it in Row Reduced Eschelon Form.\[\Large\rm \left(\begin{array}{rrr|r}3&3&2&-5\\ 1&1&3&-4\\2&2&5&-7\end{array}\right)\]Remember with the zeroes and only 1's along the diagonal? :d Or you prefer other method maybe? Like substitution or something?
Yea I don't remember it like that? @zepdrix
That would be D
@solver explain why
This website explains it all http://www.algebrahelp.com/calculators/equation/ Don't worry, it doesn't tell you the answer directly, it gives out steps.
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