2x - 3y - 4z = -21 -4x + 2y - 3z = -14 -3x - 4y + 2z = -10
SO, can you spilt it up into 3 eq for me? HINT: They will all =-10
2x - 3y - 4z = -21 -4x + 2y - 3z = -14 -3x - 4y + 2z = -10
what happened to your -21 in the second?
and your -14 in the 3rd?
or, is it already 3 eq not one bog long eq?
it was meant to be on the equation before
yes its 3 equations
ok so there are a few ways to solve a system of three equations
i tired eliminating and i just cant do it
tried*
1. you solve the others for a variable that is convenient then plug and chug. 2. you turn it into a matrix and put it into reduced row echelon form 3. you add or subtract eq. So, if you know linear algebra2 is the easiest. If you don't 3 is the easiest.
Try this for me, add 2 times equation 1 to eq. 2
what do you mean?
ie if I had 4x+2y=6 and -8x+3y=12 I would add 2 times eq 1 to two like so 2(4x+2y)=2(6) 8x+4y=12 so now, + -8x+3y=12 -------------------- 0x+7y=24 so then you get 7y=24 and y=24/3 Do you see?
Also, this may help more: https://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/fancier-systems/v/systems-of-three-variables
its 3 variables though
Same idea
i will try it again then
You do the same thing
ok
Show every step please, even the teeny weeny ones
alright
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