Question

chemistry

Answer 1

Well, this is a Lab Manual... Just Explains all Your Doubt..

Hope It Helps ! @Ash90

Answer 2

i don't see how to do the equation though on this

Answer 3

Alright, u need the equations..
Just a min..

Answer 4

yes that's the only thing i'm having trouble with

Answer 5

Moles CaCO3 = 1.00 g/ 100.09 g/mol= 0.00999
CaCO3 + 2 HCl >> CaCl2 + H2O + CO2


Moles NaHCO3 = 1.00 g/ 84.007 g/mol=0.0119
NaHCO3 + HCl >> NaCl + H2O + CO2


Moles Mg(OH)2 = 1.00 g/ 58.33 g/mol=0.0171
Mg(OH)2 + 2 HCl >> MgCl2 + 2 H2O


Moles Al(OH)3 = 1.00 g / 78.00 g/mol= 0.0128
Al(OH)3 + 3 HCl >> AlCl3 + 3 H2O

Answer 6

Does It help ?

Answer 7

yes so what you did was take the weight of each and divide it by 1.00g correct?

Answer 8

Exactly, You Are Incredible..!!

Answer 9

thanks now i know how to do it. thanks a lot

Answer 10

Close the question if You are happy with the answers! Agin, Wish You a Good Day !

Answer 11

thank you