Question

Help me show my work please?

3. Which equation represents a line with a slope -1/2 that passes through (-3, 4)

Answer: 2y + x = 5

Answer 1

How did you approach the problem ?

Answer 2

I tried to do it, and then asked my sister to help but, i'm confused.

Answer 3

Okay no problem

Answer 4

See when I am given the slope of a line and a point passing through it, I can use this form of the line:

\(\large{(y-y_1) = m*(x-x_1)}\)

Here, \((x_1,y_1)\) is the point lying on the line ; m is the slope of the line.

Answer 5

Now can you solve it ?

Answer 6

hold on , let me try that

Answer 7

Go on.

Answer 8

could you use my equation but, with different numbers with the form you gave me as an example, cause i still didn't get it right

Answer 9

No problem

Answer 10

I am going to change the question to this :\(\color{blue}{\text{Originally Posted by}}\) @Mclovin21

\(\text{3. Which equation represents a line with a slope}~ \color{red}{1/2}~\text{that passes through}~ \color{red}{(-2, 1)}\)

\(\color{blue}{\text{End of Quote}}\)

Answer 11

\(\color{blue}{\text{Originally Posted by}}\) @vishweshshrimali5
Now, if I compare the equation I wrote and the question, I see that:

(1) The line passes through (-2,1),so, (-2,1) is the same as \((x_1,y_1)\).

So, \(x_1 = -2\); \(y_1 = 1\).

(2) The line has a slope 1/2, but, for the equation I wrote, the slope was m. So,

\(m = \cfrac{1}{2}\).

Thus, the equation of the required line will be:

\(\large{(y-y_1) = m(x-x_1)}\)

or, \(\large{(y-1) = \cfrac{1}{2}(x-(-2))}\)

or, \(\large{(y-1) = \cfrac{1}{2}(x+2)}\)

or, \(\large{(y-1)*2 = 1*(x+2)}\)

or, \(\large{2y - 2 = x+2}\)

or, \(\large{2y-x = 4}\)

This is the require equation line.

Observe this solution carefully and try solving your question.
\(\color{blue}{\text{End of Quote}}\)

Answer 12

how did you get the *2 after (y-1) in the equation (y - 1) *2 = 1 * (x + 2)??

Answer 13

I actually multiplied 2 both sides, so that I could cancel out the 2 in denominator in RHS.