Question

A cruise ship travels 330 miles due east before turning 25 degrees north of east. It travels 180 miles along its new course. How far is the cruise ship from its initial position?

a.210 miles
b.499 miles
c.301 miles
d.295 miles

Answer 1

use Law of Cosines
\[x^2 = 330^2 + 180^2 -(330)(180)\cos 155\]

Answer 2

498.97
b.

Answer 3

thank you. did i get these 2 correct?

Answer 4

so for the first one, thats law of cos so a^2 = b^2 + c^2 - 2(b)(c)cosA

Answer 5

so a^2 = 81 + 121 - 2(9)(11)cos65

Answer 6

a^2 = 202 - 198cos65

Answer 7

its about 10.9. from there do the law of sines.

Answer 8

so sinA/a = sinB/b
for you thats sin65/10.9 = sinB/9

Answer 9

i got about 48.4

Answer 10

you can check it since im not writing this down in front of me, but ya, thats how i got that answer

Answer 11

so me being me, im gonna change XYZ to ABC where youre solving for the measure of angle C

Answer 12

so again, law of cosines, c^2 = a^2 + b^2 - 2(a)(b)cosC

Answer 13

15^2 = 21^2 + 27^2 - 2(21)(27)cosC

Answer 14

225 = 441 + 729 - 1134cosC

Answer 15

225 = 1170 - 1134cosC. subtract the 1170... -945 = -1134cosC

Answer 16

long complicated number.... inverse cosine of that...

Answer 17

I got 33.9 as my answer.

Answer 18

so closest is 34 deg

Answer 19

I calculate 33.557°