Ask your own question, for FREE!
Mathematics 77 Online
OpenStudy (anonymous):

http://i.imgur.com/Bulb6ue.png 1. The graph shows the first three terms in a geometric sequence. A. What is the common ratio r? Explain how you determined your answer. B. What is the recursive formula for the sequence? C. What is the iterative formula for the sequence? D. Show how to use your answer from Part C to find the eighth term of the sequence.

ganeshie8 (ganeshie8):

for part A : common ratio = (next term) / (present term)

ganeshie8 (ganeshie8):

just take the ratio of 2nd and 1st terms

ganeshie8 (ganeshie8):

look at the graph : first term = ? second term = ?

OpenStudy (anonymous):

First Term: 2 Second term: 5 ??

ganeshie8 (ganeshie8):

Yes ! common ratio = (second term)/ (first term) = ?

OpenStudy (anonymous):

0.4?

ganeshie8 (ganeshie8):

common ratio = (second term)/ (first term) = 5/2

ganeshie8 (ganeshie8):

leave it in fraction form

OpenStudy (anonymous):

So the common ratio is 5/2, I can write that down?

ganeshie8 (ganeshie8):

Yep !

OpenStudy (anonymous):

Awesome, and B? How do I find the recursive formula?

ganeshie8 (ganeshie8):

multiplying the common ratio to present term gives u the next term, so the recursive formula is : \(\large a_{n+1} = a_n \times r = a_n \times \dfrac{5}{2} = \dfrac{5}{2}a_n\)

OpenStudy (anonymous):

Great, thank you! And C, D please

ganeshie8 (ganeshie8):

for part C, use the general term of geometric sequence formula : \(\large a_n = a_1r^{n-1}\)

ganeshie8 (ganeshie8):

You knw \(\large a_1 = 2\), \(\large r = \dfrac{5}{2}\) plug them in above formula^

OpenStudy (anonymous):

5?

ganeshie8 (ganeshie8):

wym 5 ?

OpenStudy (anonymous):

2*5/2= 5(x-1) that's my answer for C right?

ganeshie8 (ganeshie8):

ahh no, just plug them in the formula, no simplification is possible...

ganeshie8 (ganeshie8):

\(\large a_n = 2\left(\dfrac{5}{2}\right)^{n-1} \)

OpenStudy (anonymous):

Ah I see, and D?

ganeshie8 (ganeshie8):

You cannot cancel 2's cuz the other 2 is under exponent

OpenStudy (anonymous):

Yeah now I see, haha took me a bit to understand. And how would I use my answer from C to find the 8th term?

ganeshie8 (ganeshie8):

just plugin n = 8 and evaluate

ganeshie8 (ganeshie8):

\(\large a_n = 2\left(\dfrac{5}{2}\right)^{n-1} \) \(\large a_8 = ? \)

OpenStudy (anonymous):

Hmm, I don't know.

ganeshie8 (ganeshie8):

\(\large a_n = 2\left(\dfrac{5}{2}\right)^{n-1} \) \(\large a_8 = 2\left(\dfrac{5}{2}\right)^{8-1} = 2\left(\dfrac{5}{2}\right)^{7} \)

ganeshie8 (ganeshie8):

use ur calculator

OpenStudy (anonymous):

1220.703125

OpenStudy (anonymous):

1220.703125

ganeshie8 (ganeshie8):

looks good^

OpenStudy (anonymous):

Awesome thanks! Do you have any more time because I have one more question?

ganeshie8 (ganeshie8):

I'll try, ask...

OpenStudy (anonymous):

http://i.imgur.com/T0wRI4i.png The matrices show the number of indoor and outdoor volunteers in different age groups. A) Create one matrix that shows the total number of indoor and outdoor volunteers in different age groups. Name the matrix T. B) What is the value of the element at t11 and what does that value indicate? C) Create a matrix by subtracting the women’s matrix from the men’s matrix. Name the matrix D. D) What is the value of the element at d12 and what does that value indicate?

ganeshie8 (ganeshie8):

Alright, so the given matrices represent men and women volunteers separately

ganeshie8 (ganeshie8):

total number of volunteers = [men volunteers] + [women volunteers]

ganeshie8 (ganeshie8):

for part A, just add both the given matrices

ganeshie8 (ganeshie8):

you familiar wid matrix addition right ?

OpenStudy (anonymous):

A bit, not too well.

OpenStudy (anonymous):

So my answer for A should look like this |dw:1402395174785:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!