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Chemistry 11 Online
OpenStudy (anonymous):

What is the volume of 0.200 mol of an ideal gas at 200 kPa and 400 K?

OpenStudy (anonymous):

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OpenStudy (somy):

PV=nRT

OpenStudy (somy):

use it

OpenStudy (somy):

V= nRT/P

OpenStudy (somy):

n= 0.200 mole P= 200 000 Pa T= 400 K R= 8.31

OpenStudy (somy):

put the values and get ur answer

OpenStudy (somy):

your answer will be in m3 so convert it to your needed unit

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