@Somy How many liters of oxygen gas, at standard temperature and pressure, will react with 35.4 grams of calcium metal? Show all of the work used to solve this problem. 2 Ca + O2 yields 2 CaO For this question would I use PV = nRT?
no this time you do not use it
find moles of calcium metal
0.8
there are 2 Ca
40.1* 2= your Mr for Ca
Oops, right. So like 2.26
Mr = 80.2 mass = 35.4
mole= mass/Mr try again
0.44
thats right)
2 Ca + O2 yields 2 CaO now ratio whats the ratio between Ca and O2?
2:1?
good so if 2- 0.44 1- ?
.22
thats right now u got moles of O2
there is a formula connecting Volume , standard temperature and pressure value, and moles
value of standard temperature and pressure is 22.4 if i remember correctly
check out your notes
Let me check real quick
yeah it's 22.4 as i thought http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html STP is http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/idegas.html
This is what I have
oh its not about this the value is in Liters and it's known so u can straightaway use 22.4dm3
OH, okay lol.
\[Volume = mole \times 22.4 \] do this and you'll get your answer :)
it's the formula for when you need to find volume or mole and you are given either one and the question is telling you that it's happening (reaction is happening) under standard temperature and pressure so do not mix it up :)
V= .22 x 22.4?
yes :)
So it's 4.93
that's right) and the unit is dm3 or Liters
liters since it's asking for that right
yup) so u don't need to convert anything :D
Awesome! Can you help me with my last one?
lets see it :)
If 5.0 liters of carbon dioxide gas are produced by the reaction below at STP, how many liters of oxygen gas were used in the reaction? 2 CO (g) + O2 (g) yields 2 CO2 (g)
use volume formula :D
and find mole of CO2
V = 12 x 22.4?
nvm wait a sec lol
u are given volume of CO2 and u know STP so find mole
5.0 = .22 x 22.4 = 4.9
omg lol 0.22???? it's from ur previous question
Volume= mole * 22.4 mole= Volume/22.4 =5.0/22.4=
LOL im all over the place
Wait so Im confused now
what u don't get?
Join our real-time social learning platform and learn together with your friends!