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Mathematics 21 Online
OpenStudy (anonymous):

Please help me! I will post the question bellow this.

OpenStudy (vishweshshrimali5):

Severus Snape ? :)

OpenStudy (anonymous):

\[(12^{2} + 9x - 7) \div 3x\]

OpenStudy (anonymous):

yes, he is the best ;)

OpenStudy (vishweshshrimali5):

Okay you will not be able to simplify it very much. Can you tell me in what form do you need the question.

OpenStudy (vishweshshrimali5):

Because, 3x is not a factor of the polynomial in the numerator.

OpenStudy (anonymous):

yes I can..it is..

OpenStudy (vishweshshrimali5):

Ohh sorry

OpenStudy (anonymous):

Well it is a polynomials

OpenStudy (vishweshshrimali5):

I read it as x^2 in in place of 12^2. My bad.

OpenStudy (anonymous):

oh haha no prob

OpenStudy (vishweshshrimali5):

Ok lets see what we have.

OpenStudy (anonymous):

alrighty then..

OpenStudy (triciaal):

should it be 12 x^2

OpenStudy (anonymous):

yes sorry, let me retype the question because I messed up

OpenStudy (vishweshshrimali5):

\[\large{(12^{2} + 9x - 7) \div 3x}\] \[\large{=(144 + 9x - 7) \div 3x}\] \[\large{=(137 + 9x) \div 3x}\] Now here is where we are stuck. Now I want to ask some questions to you before continuing. Are we dividing by (3x) as complete or only 3 and then multiplying by x ?

OpenStudy (anonymous):

\[(12x ^{2} + 9x - 7) \div 3x\]

OpenStudy (triciaal):

|dw:1402422094769:dw|

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