Please help me!
I will post the question bellow this.
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OpenStudy (vishweshshrimali5):
Severus Snape ? :)
OpenStudy (anonymous):
\[(12^{2} + 9x - 7) \div 3x\]
OpenStudy (anonymous):
yes, he is the best ;)
OpenStudy (vishweshshrimali5):
Okay you will not be able to simplify it very much. Can you tell me in what form do you need the question.
OpenStudy (vishweshshrimali5):
Because, 3x is not a factor of the polynomial in the numerator.
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OpenStudy (anonymous):
yes I can..it is..
OpenStudy (vishweshshrimali5):
Ohh sorry
OpenStudy (anonymous):
Well it is a polynomials
OpenStudy (vishweshshrimali5):
I read it as x^2 in in place of 12^2.
My bad.
OpenStudy (anonymous):
oh haha no prob
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OpenStudy (vishweshshrimali5):
Ok lets see what we have.
OpenStudy (anonymous):
alrighty then..
OpenStudy (triciaal):
should it be 12 x^2
OpenStudy (anonymous):
yes
sorry,
let me retype the question because I messed up
OpenStudy (vishweshshrimali5):
\[\large{(12^{2} + 9x - 7) \div 3x}\]
\[\large{=(144 + 9x - 7) \div 3x}\]
\[\large{=(137 + 9x) \div 3x}\]
Now here is where we are stuck.
Now I want to ask some questions to you before continuing. Are we dividing by (3x) as complete or only 3 and then multiplying by x ?
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