Question

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Answer 1

To make life easier,\[\large \sum_{n = 1}^{5}3(-2)^{n - 1} = 3\underbrace{\sum_{n = 1}^{5}(-2)^{n-1}}_{\text{evaluate this}}\]

Answer 2

There are many ways to find out the value of the new sum. Do you need to do it by hand, or through some other ways?

Answer 3

I don't have to do it by hand.

Answer 4

All it's asking for is the answer

Answer 5

No, I mean do you need to employ the traditional methods of evaluating a sum by plugging in each of the values, or through another "hacky" way?

Answer 6

Ahhhh I have no idea lol

Answer 7

It literally doesn't matter as long as I get the right answer

Answer 8

\[3\large \sum_{n = 1}^{5}(-2)^{n - 1} =3\left( (-2)^0 + (-2)^1 + (-2)^2 + (-2)^3 + (-2)^4\right)\]

Answer 9

Oh, are you on your finals?

Answer 10

33?

Answer 11

No

Answer 12

was 33 right?

Answer 13

If you think it is right, it is right.