Question

Given a mean of 259 and a standard deviation of 229.1, what is the z-score of the value 78 rounded to the nearest tenth

Answer 1

the equation for this is:
\[z=\frac{ x-mean }{ standard deviation}\]
so we'd get
\[z=\frac{ 78-259 }{ 229.1 }\]

Answer 2

solve for z @Deja_Deja

Answer 3

@alexwee123 i got -0.790 . so the nearest tenth would be -0.8 . correct ?

Answer 4

yep!