Question

A researcher wants to conduct a genetic study using 15 randomly-selected volunteers. He has a volunteer pool of 30, composed of 15 males and 15 females. What is the probability that the randomly-selected group will be all male OR all female?
A. 1/155,117,520
B. 1/77,558,760
C. 1/310,235,040
D. 1/450

Answer 1

@AndrewKaiser333

Answer 2

I honestly do not know much for probability never had to go through it yet this year. my guess would be D. or B. but i would rather you ask hero, thomaster or sattelite so since i said that i will recommend them now
@thomaster @Hero @satellite73

Answer 3

@thomaster @Hero @satellite73

Answer 4

sorry I am kinda stumped because I never went through it like I said but i gave you my guesses and recommended 3 great math people who have been through this subject I think.

Answer 5

thank you

Answer 6

np hun

Answer 7

@ajaylounsber

Answer 8

@joanip_

Answer 9

I completed the calculation

Answer 10

I don't know, sorry :s

Answer 11

@Hero okay what did u come up with

Answer 12

Basically:
The probability that the 1st selected will be male is \(\dfrac{15}{30}\)

The probability that the 2nd selected will be male is \(\dfrac{14}{29}\)

The probability that the 3rd selected will be male is \(\dfrac{13}{28}\)

And so on

The probability that the 15th selected will be male is \(\dfrac{1}{16}\)

So the probability that the first 15 selected will be all male is
\(\dfrac{15}{30} \dot\ \dfrac{14}{29} \dot\ \dfrac{13}{28}...\dfrac{1}{16} = \dfrac{1}{155117520}\)

The probability that the first 15 selected will be all female is
\(\dfrac{15}{30} \dot\ \dfrac{14}{29} \dot\ \dfrac{13}{28}...\dfrac{1}{16} = \dfrac{1}{155117520}\)

Therefore the probability that the first 15 selected will be all male or all female is

\( \dfrac{1}{155117520} + \dfrac{1}{155117520}\)

Answer 13

thank you soooo much ! do u feel like answering another question? Its answered but i want to make sure its right @Hero