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OpenStudy (anonymous):
\[(4-3\left( \sqrt{2} \right)^2\]
4-3 becomes 1, so you end up with
\[\left( \sqrt{2} \right)^2\]
and the sqroot cancels with the power, so your answer would be 2
OpenStudy (isaiah.feynman):
Umm not quite..
OpenStudy (isaiah.feynman):
This is an expansion problem.
OpenStudy (isaiah.feynman):
\[(a-b)^{2} = a^{2}-2ab+b^{2}\]
OpenStudy (jim766):
\[(4-3\sqrt{2})(4-3\sqrt{2})\]
foil it
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OpenStudy (jim766):
\[16 -12\sqrt{2}-12\sqrt{2}+9(2)\]
OpenStudy (anonymous):
so whose correct? and thanks for all who is trying to help
OpenStudy (isaiah.feynman):
Both ways are the same.
OpenStudy (jim766):
mine is not done...need to combine like terms..
OpenStudy (anonymous):
and I dont know if I asked it correctly but its (4-3\[\sqrt{2}\])\[^{2}\]
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OpenStudy (anonymous):
dang it
OpenStudy (anonymous):
is 16−122√−122√+9(2) as simple as it can get?
OpenStudy (isaiah.feynman):
Nope.
OpenStudy (isaiah.feynman):
Add the 12s and multiply 2 and 9.
OpenStudy (anonymous):
typed it in my calculator and got 0.0588 which is correct
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OpenStudy (isaiah.feynman):
Good. You might wanna do whole numbers next time instead of decimals.
OpenStudy (anonymous):
16√2√2+9(2)?
OpenStudy (anonymous):
16*1+18?
OpenStudy (anonymous):
i feel that is very wrong
OpenStudy (isaiah.feynman):
Yes it is. The simplified form is \[16-24\sqrt{2}+18 = 34-24\sqrt{2}\]
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