Question

Simplify (x-4) (x^2+3x-1) please I need help

Answer 1

what i got was x^3-x^2-13x+4

Answer 2

i did that by multiplying everything in (x^2 + 3x -1) by x and then by 4 and combined like terms

Answer 3

sure

Answer 4

ok ARoC (average rate of change) = change in y over change in x. so from -3 to 5, you y changed by 8 and from -3 to 1, your x changed by 4 so 8/4 = 2.
your ARoC is 2

Answer 5

take (3xy-18y) + (2x-12)

take out 3y in the first part so you have 3y(x-6) and then take out 2 in the other part so you have 2(x-6).

so. 3y(x-6)+2(x-6)

Answer 6

so then in the end you should get (x-6)(3y+2)

Answer 7

ya

Answer 8

we get the same thing we just got it different ways

Answer 9

course :)

Answer 10

yes, it is

Answer 11

ill check it, gimme a sec.

Answer 12

Yes, 43 is correct

Answer 13

yes. so first i found t(4) = 4(4)+3 so t(4)= 19. next i found c(19) = 2(19) + 5 = 43

Answer 14

( thank you for your testimonial :) im glad to know im helping)

Answer 15

im happy to help whenever :)

Answer 16

im figuring out the how but your answer should be\[4\sqrt[4]5{}\]

Answer 17

https://www.desmos.com/calculator/2npgb907ik

Answer 18

C is your answer

Answer 19

yes, youre right

Answer 20

if you change c into y=mx+b form, you get y-3=2x-4. add the 3, y=2x-1 which is the same as the line i first gave you :)

Answer 21

ok so before you even plug in 3, find the inverse of your original equation. do you know how to do that?

Answer 22

im not sure if you responded...my computer hates me XD

Answer 23

if you didnt, then the way you find it is you basically realize that f(x) is a fancy way of saying y, so you switch the x and the y in your problem and resolve again for y. so
x = (y-5)/3

Answer 24

solve for y

Answer 25

your inverse function is 3x+5. now substitute 3 in for x and you get 9+5 which is 14 so yes you got it correct, good job

Answer 26

sorry, had to go take food out of the oven before my house burns to the ground XD

Answer 27

worthy cause XD

Answer 28

Yes, your answer is B

Answer 29

ok. the conjugate of a complex number is a long and complicated way of saying leave the real number alone, change the sign of the imaginary number

Answer 30

so since 2 is your real and -8i is your imaginary, change the - to a +8i and you get 2+8i

Answer 31

here, this explains it http://www.mathwords.com/c/complex_conjugate.htm

Answer 32

awesome :)

Answer 33

anything else you need help with?

Answer 34

i got all the time you need :)

Answer 35

sure thing. :) youre talking to an insomniac, i got a lot of time XD

Answer 36

do you know the x factor? it makes things pretty simple to at least see

Answer 37

in an equation where there is a number before your x^2, multiply that number by your last number

Answer 38

so you have

\ 68 /
\ /
\ /
\/
/ \
/ \
/ \
/ 16 \


just pretend that looks decent for me XD

Answer 39

now you find what number multiplies to make 68 and adds to make 16

Answer 40

D is your answer

Answer 41

im just confusing you XD sorry.

Answer 42

haha thank you

Answer 43

A. 2. im figuring out how to explain that though....

Answer 44

ill check right now

Answer 45

here, @awkwardpanda will also help too :)

Answer 46

ya, but im gonna be eating at the same time and i dont want my answers to get too delayed XD

Answer 47

there they are :)

Answer 48

ok for that one, you could do solving using the quadratic formula. but for me its easier to subtract 20 and have 2x^2+3x -20 = 0

Answer 49

so what multiplies to -40 and adds to 3?

Answer 50

yes good job :)

Answer 51

im sorry, i was eating

Answer 52

ok this one might take me a little so hold on a sec

Answer 53

im lazy so im just gonna plug the #s in XD

Answer 54

B.

Answer 55

anything else ya need?

Answer 56

sure thing. dont really got anything better to do XD

Answer 57

sorry about this but your messages (if there are any) arent coming in all that well on my comp. so i cant tell if youre saying anything or not...

Answer 58

ok now this one goes
y=50.
y=10x
and y=5x+20

Answer 59

do you see why?

Answer 60

anything else?

Answer 61

alright

Answer 62

yes, they both started with the same expression. figuring out how they got their answers

Answer 63

they both started with x^(1/3)

Answer 64

im not too sure about this one, sorry.

Answer 65

yeah, im not the best at word problems XD

Answer 66

any parabola such as y=x^2 would work, the focus of y=x^2 is at (0,1/4) and the directrix y=1/4

Answer 67

cool :)