Given f(x)= x-5/3, solve for f^-1 (3)

Question

anonymous · Answer

To find the inverse:

Replace f(x) with y
Switch x's and y's, so put x where y is and x where y is.
Solve for y
Replace y with f^-1(x)

anonymous · Answer

Also, 
which of the following is the conjugate of a complex number with 2 as the real part and -8 as the imaginary part?

anonymous · Answer

very confused, let me read that

anonymous · Answer

I did that and couldn't get the answer @iambatman

anonymous · Answer

Show me.

anonymous · Answer

x=y-5/3

anonymous · Answer

i honestly don't know

anonymous · Answer

Let's follow the steps, and we'll worry about f^-1(3) after.

the_fizicx99 · Answer

$\ \sf \Large f(x) = \dfrac{x - 5}{3} $

1. replace f(x) with y
2. Switch x where y is and x where y is.
3. Solve for y again.

x = $\ \sf \dfrac{y - 5}{3} $

3x = y - 5

3x + 5 = y

Replace the "y" you just solved for with $\ f^{-1}(x) $

And that's your inverse function, $\ \sf f^{-1}(x) = 3x + 5 $

Now plug in 3 for "x" and that'll be f^-1(3)

anonymous · Answer

f(x) = x-5/3
y = x-5/3
x = y - 5/3

You got up to that point, so nice. Now solve for y.

x+5/3 = y
f^-1(x) = x+5/3

Now just plug in the 3 

f^-1(3) = 3+5/3

You can do that at least :)

anonymous · Answer

Oh is it x-5/3 or (x-5)/3 >_>

anonymous · Answer

Either way you have answer from both sides, ty fizi :3

anonymous · Answer

I got 14

anonymous · Answer

Thankyou