Calculus 1!!
find the intervals on which f is continuous:
1/(x+5^2)+10
Answer is: (-∞,∞)

So I did this:
1/(x+5)² +10
-- (x² +10x+25)
--(5,5)
But I am getting on the wrong track!! What steps do I take to get (-∞,∞)?? Can anyone help for a best answer? Please and thank you!!

Question

Calculus 1!!
find the intervals on which f is continuous: 
1/(x+5^2)+10 
Answer is: (-∞,∞) 

So I did this: 
1/(x+5)² +10 
--> (x² +10x+25) 
-->(5,5) 
But I am getting on the wrong track!! What steps do I take to get (-∞,∞)?? Can anyone help for a best answer? Please and thank you!!

anonymous · Answer

You must have a typo because the function you gave is not continuous on (-inf,inf)

anonymous · Answer

I know!!! The answer key said that it was supposed to be (-inf, inf).  So what is the real answer supposed to be??? I got (-∞,-5),(-5,∞). But the other two answer choices were; b) (-∞,-40),(-40,∞) and d) (-∞,35),(35,∞)

anonymous · Answer

The plus 10 is supposed to be part of the denominator by the way! The problem is supposed to look like (1)/[(x+5²)+10]

anonymous · Answer

find the domian and that;s your answer

unklerhaukus · Answer

$$\frac1{(x+5^2)+10}\
\frac1{(x+25)+10}\
\frac1{x+35}\
$$

i think there is typo in question

anonymous · Answer

I think the question is:$$\frac{ 1 }{(x+5)^{2}+10 }$$

If that is the case, $$(x+5)^{2}$$ will never be negative.  Therefore the min value of the denominator is 10.  So for all values of x, the denominator will not be 0.  Therefore it is continuous on $$(-\infty, \infty)$$