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How to differentiate 2e^y
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\[\frac{ d }{ dy }2e^y = 2e^y\]
Remember the derivative of e^x = e^x
Well there's a proof, it requires limits, and \[\frac{ d }{ dx }lnx=\frac{ 1 }{ x }\]
Basically \[\frac{ d }{ dx } e^x = e^x \implies \frac{ d }{ dx } lnx =\frac{ 1 }{ x }\] \[\frac{ d }{ dx }(\ln(e^x)) = \frac{ d }{ dx }xlne=\frac{ d }{ dx }x =1 \]
But you can use the chain rule, with the same derivative.
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Simpler, I'd say...
\(\Large \color{green}{ლ(́◉◞౪◟◉‵ლ)}\)
\[f(x)=2e^y\\ f'(x)=2e^y\frac{\mathrm d y}{\mathrm dx}\]
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