Question

.

Answer 1

max of sine is 1, min is -1
replace \(\sin(\frac{\pi t}{5})\) by 1 and see what you get

Answer 2

\[20 \sin (\pi t/5) + 12 \]\[20 \overbrace{\sin (\pi t/5)}^{\text{ put a 1 here}} + 12 \]

Answer 3

then
\[20 \overbrace{\sin (\pi t/5)}^{\text{ put a -1 here}} + 12\]

Answer 4

20 + 12 = 32 for the maximum?

Answer 5

yes

Answer 6

no

Answer 7

\(-20+8\)