g(x)=X^2-1 Find the x and y intercept
do you mean g(X)=x^2-1 ???
oh yes sorry
\(\large\color{blue}{ \rm g(x)=x^2-1 }\) \(\large\color{blue}{ \rm HINT:~~~~~~~~~~~~~~~x^2-1=(x-1)(x+1) }\)
1 and -1
oh so i had to factor it to get my x and y?
you would factor it and then set each factor, (x-1) and (x+1) equal to zero to find your x-intercept
oh ok thanks for the help :)
Have you learned about imaginary numbers (such as ` i ` ) ?
i have a question is this question same thing when written as (x^2-1) in parenthesis?
Well, when you write ` 3-1 ` , and ` (3-1) ` the meaning is the same. THe difference would be between \(\large\color{blue}{ \rm f(x)=x^2-1 }\) and \(\large\color{blue}{ \rm f(x)=(x-1)^2 }\)
yes but my teacher said we are not messing with imaginary numbers yet
cool. I am just saying that if you had a plus instead of minus, in \(\large\color{blue}{ \rm f(x)=x^2-1 }\) you would need imag. .....
oh ok thanks again :)
Anytime :)
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