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OpenStudy (anonymous):
you would factor it and then set each factor, (x-1) and (x+1) equal to zero to find your x-intercept
OpenStudy (awesome781):
oh ok thanks for the help :)
OpenStudy (solomonzelman):
Have you learned about imaginary numbers (such as ` i ` ) ?
OpenStudy (awesome781):
i have a question is this question same thing when written as (x^2-1) in parenthesis?
OpenStudy (solomonzelman):
Well, when you write ` 3-1 ` , and ` (3-1) ` the meaning is the same.
THe difference would be between
\(\large\color{blue}{ \rm f(x)=x^2-1 }\) and \(\large\color{blue}{ \rm f(x)=(x-1)^2 }\)
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OpenStudy (awesome781):
yes but my teacher said we are not messing with imaginary numbers yet
OpenStudy (solomonzelman):
cool. I am just saying that if you had a plus instead of minus, in \(\large\color{blue}{ \rm f(x)=x^2-1 }\) you would need imag. .....