Question

Simplify: (sin theta - cos theta) - (sin theta + cos theta)^2

Answer 1

I'm following you!

Answer 2

\(\large\color{midnightblue}{ \rm (sinθ - cosθ) -(sinθ+cosθ)^2 }\)
\(\large\color{midnightblue}{ \rm (sinθ - cosθ) -(sin^2θ+2sinθ~cosθ+cos^2θ) }\)
\(\large\color{midnightblue}{ \rm sinθ - cosθ -sin^2θ-2sinθ~cosθ-cos^2θ }\)
\(\large\color{midnightblue}{ \rm sinθ - cosθ -2sinθ~cosθ-sin^2θ-cos^2θ }\)
\(\large\color{midnightblue}{ \rm sinθ - cosθ -sin(2x)- sin^2θ-cos^2θ }\)
\(\large\color{midnightblue}{ \rm sinθ - cosθ -sin(2x)- 1( sin^2θ+cos^2θ) }\)
\(\large\color{midnightblue}{ \rm sinθ - cosθ -sin(2x)- 1( 1) }\)
\(\large\color{midnightblue}{ \rm sinθ - cosθ -sin(2x)- 1 }\)

Answer 3

No x, just theta, when I say x I mean theta.

Answer 4

I don't know what to do from ..... \(\large\color{midnightblue}{ \rm sinθ - cosθ -sin(2θ)- 1 }\)

Answer 5

Sorry -:(

Answer 6

You know what, that's totally fine. You at least attempting to help and give your input is worth giving you a medal.

Answer 7

@SolomonZelman

Answer 8

That's nice of you :)

Answer 9

I did all the calculations and applied everything I can to do it. But I am pretty sure what I wrote is the simplest, unless the question is miss-written.