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Mathematics 16 Online
rishavraj (rishavraj):

6 married couples are standing in a room. If 4 people are chosen at random, then the chance that exactly one married couple is among the 4 is???

OpenStudy (dan815):

@ganeshie8

rishavraj (rishavraj):

No need to bother dan815... i got it done

OpenStudy (dan815):

may i see your solution

rishavraj (rishavraj):

yeah...for sure..hold on

ganeshie8 (ganeshie8):

P(choosing any one couple) = (6 choose 1)/(12 choose 2)

ganeshie8 (ganeshie8):

So P(Success) = 1/11 P(not Success) = 10/11

rishavraj (rishavraj):

rishavraj (rishavraj):

@dan815 got it??

OpenStudy (dan815):

not yet, how to carry on ganeshie? 1/11 success and 10/11 fail

rishavraj (rishavraj):

see total ways of selecting 4 people = 12C4

OpenStudy (dan815):

yes

rishavraj (rishavraj):

now we need one couple...so it would be 6C1....which means we have chosen 2 persons...now we need to get 2 more people which r not couple

OpenStudy (dan815):

right

rishavraj (rishavraj):

so we select 2 couples from the left 5C2..and after that we select one person from each two couple we chose...it would be 2C1*2C1

OpenStudy (dan815):

thats cool

OpenStudy (dan815):

didnt think you can think of picking 2 people out of the 5 left couples like that

ganeshie8 (ganeshie8):

very nice :)

ganeshie8 (ganeshie8):

reminds me of subcommittees problems

rishavraj (rishavraj):

@dan815 yeah u can...but it wont assure that the two chosen from the 5 couples left wouldnot belong to the couple

OpenStudy (dan815):

what do you mean by that i dont see why they wouldnt belong to a couple

OpenStudy (dan815):

why they would*

ganeshie8 (ganeshie8):

another way is to take the negation : (10 choose 2) - (5 choose 1)

rishavraj (rishavraj):

the question says that there must be exactly one married couple among the 4

ganeshie8 (ganeshie8):

that gives u all the possible combinations for NOT-COUPLE ^

OpenStudy (dan815):

right wont this give you only 1 couple

ganeshie8 (ganeshie8):

(10 choose 2) - (5 choose 1) is replacement for (5 choose 2)*(2 choose 1)*(2 choose 1)

OpenStudy (dan815):

howd u get that genshie

OpenStudy (dan815):

10C2-5C1

ganeshie8 (ganeshie8):

pick two people from the remaining 10 people : 10C2

ganeshie8 (ganeshie8):

subtract all the possible couple combinations : 5C1

OpenStudy (dan815):

oh i see 5c1 ways to pick the remaining couple

OpenStudy (dan815):

so u subtracting froom all combinations that

OpenStudy (dan815):

okk thats cool :)

rishavraj (rishavraj):

@LeilaJudeh

OpenStudy (anonymous):

PPPPPPPPPPPPPUUUUUUUUUUUUUUUUUUUUUUUUUUUUUPPPPPPPPPPPPPPPPPPPPPPPPPPYYYYYYYYYYYYYYYYYYYYYYYYYYY

rishavraj (rishavraj):

lol....xD stray one

OpenStudy (anonymous):

I WANT IIIIIIIITTTTTTTTTTTTTTTTTTTTTT

rishavraj (rishavraj):

practically not possible.....lol..xDq

OpenStudy (anonymous):

BUT I WANT IT ;-;

rishavraj (rishavraj):

i can't help then.......xD

OpenStudy (anonymous):

rishavraj (rishavraj):

@LeilaJudeh wow u r as cute as him..<3 .....lmao....xD

OpenStudy (anonymous):

hahahahaha ty ty xDDD

rishavraj (rishavraj):

@LeilaJudeh

rishavraj (rishavraj):

OpenStudy (anonymous):

PPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

rishavraj (rishavraj):

his eyes??

OpenStudy (anonymous):

so cute ;-;

rishavraj (rishavraj):

loll.....xD

rishavraj (rishavraj):

here

rishavraj (rishavraj):

@LeilaJudeh

OpenStudy (anonymous):

Ty love <333

rishavraj (rishavraj):

u r most welcome.... ^^ @LeilaJudeh

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