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Mathematics 8 Online
OpenStudy (anonymous):

For the series 1+4+16+64+ a sub 1 =

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm 4^0,~4^1,~4^2,~4^3 .... }\)

OpenStudy (solomonzelman):

what is ` a sub 1 ` ?

OpenStudy (anonymous):

a with a little one below it

OpenStudy (solomonzelman):

\(\Large\color{blue}{ \bf a_1 }\). Like this ?

OpenStudy (anonymous):

yes how you do that

OpenStudy (solomonzelman):

\(\large\color{midnightblue}{ \rm a_1 }\) is the 1st term of the sequence \(\large\color{midnightblue}{ \rm a_2 }\) is the 2nd term of the sequence \(\large\color{midnightblue}{ \rm a_3}\) is the 3rd term of the sequence \(\large\color{midnightblue}{ \rm a_4 }\) is the 4th term of the sequence \(\large\color{midnightblue}{ \rm a_5 }\) is the 5th term of the sequence Use, ` \(\large\color{ black }{ \rm a_1 }\) ` color font text

OpenStudy (anonymous):

so you are saying it would be 1

OpenStudy (solomonzelman):

` \(\large\color{ black }{ \rm a_1 }\) ` gives \(\large\color{ black }{ \rm a_1 }\)

OpenStudy (anonymous):

yes I understand that thx but would a_1 =1 from the question above

OpenStudy (solomonzelman):

Also, you can use different sizes such as, ` \tiny ` ` \scriptsize ` ` \small ` ` \normalsize ` ` \large ` ` \Large ` ` \LARGE ` ` \huge ` ` \Huge ` Yes, \(\large\color{ black }{ \rm a_1=1 }\)

OpenStudy (anonymous):

I will try to do that and thx for the help

OpenStudy (solomonzelman):

Anytime :)

OpenStudy (anonymous):

forthe series 2+ (-4) +8 (-16) + r=

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