Question

Word problem help?

Answer 1

Just out of curiousity, does \(s(x) = (1.05)^{x - 1}\) ?

Answer 2

yep!

Answer 3

@Hero

Answer 4

I see. The previous problem I helped you with was of the form \(y = ab^x\)

This problem also has the same form.

In this case,
\(y = f(x)\)
\(a = h(x)\)
\(b^x = s(x)\)

Answer 5

In other words, in this case the new function can be represented by

\(f(x) = h(x)s(x)\)

I'll leave the rest for you to setup if you can figure it out.

Answer 6

Hm, okay, I'll see what I get

Answer 7

Thank you!

Answer 8

\(f(x)\) is just the name of the NEW function. Concentrate on setting up the right side of the equation though.

Answer 9

I understand the set up, I'm just kinda confused on how to multiply it all together?

Answer 10

f(x)=(200)(1.05)^x-1 like how do that?

Answer 11

What do I do with the x-1?

Answer 12

Yes that's a good start, but write it this way:

f(x) = 200(1.05)^(x - 1)

Answer 13

The parentheses emphasizes that the entire x - 1 is in the exponent.

Answer 14

Basically, you don't need to do anything else after that. The final form of the new equation is

\(f(x) = 200(1.05)^{x - 1}\)

There is no further multiplication needed.

Answer 15

@madisonvictoriaa, it is not possible to multiply 200 by 1.05 in this case because the 1.05 is raised to exponent (x - 1)

Answer 16

Actually, I think I know how to. I appreciate your help!

Answer 17

What do you mean you think you know how to? Can you show me what you are planning to do for this problem?

Answer 18

Let's see what wolframalpha says about it:

Look at the "Result" box
http://www.wolframalpha.com/input/?i=multiply%28200%281.05%29%5E%28x+-+1%29%29

Answer 19

@madisonnvictoriaa

Answer 20

I see. Well, good luck with it. Remember, equations are mathematical sentences that can be translated to English.