Question

6x/x2-4/3x-9/2x+4=
6x/(x+2)(x-2)
/
3(x-3)/2(x+2)=
6x/(x+2)(x-2)*2(x+2)/3(x-3)=
6x/(x-2)*2/3(x-3)
am I on the right track??? HELP!!!

Answer 1

I think you should use the equation editor or use more brackets at the very least to make your question clearer.

Answer 2

It's a fraction equation divided by a fraction equation.
6x
___
x^2-4
----- =
3x-9
_______
2x+4

Answer 3

@Chauncy, \(\dfrac{6x}{x^2 - 4} \div \dfrac{3x - 9}{2x + 4}\) right?

Answer 4

YES!!!

Answer 5

What if it were \(\dfrac{1}{3} \div \dfrac{1}{2}\) ? Would you know what to do in this case?

Answer 6

Yes. invert 1/2 to 2/1 and multiply numerator and denominator.
2/3

Answer 7

Well, you do something similar with the problem you're working with :)

Answer 8

Can you figure out what that is?

Answer 9

Kind of.

Answer 10

Mind sharing what you think should be done for the next step?

Answer 11

I reduced to lowest term thedenominator of first fraction. numerator and denominator of second fraction. I then inverted the numerator and denominator of second fraction.

Answer 12

\[\frac{ 6x }{ x2-4}\div \frac{ 3x-9 }{2x+4 }= \frac{ 6x }{ (x+2)(x-2) }\times \frac{ 2(x+2) }{ 3(x-3) }=\frac{ 6x }{ x-2 }\times \frac{ 2 }{ 3(x-3) }\]

Answer 13

@HERO

Answer 14

I apologize for my lack of computer savvy. I can do this, but I need some extra attention. Please let me know where I am going wrong. ANYBODY!!!