I can't understand Normality and Equivalent weight?
@JFraser
i don't use these terms either, they are terribly out-dated. normality is a term of concentration, and equivalent weight usually means "stoichiometrically equivalent", so if the equivalent reactant is 1 mole, the equivalent weight is the molar mass
Can we take an example here?
For better understanding.
H2SO4 + 2OH-= 2H2O + SO42-
Let us take that as example ^
\(H_2 SO_4 + 2 OH ^{-} \rightarrow 2H_2 O + {SO_4 }^{2-}\) How to calculate the equivalent weight of \(H_2 SO_4\) here? @chmvijay and @jfraser
H2SO4 Molecular weight of sulfuric acid (H2SO4) = 98.07 g/mol Theoretical Equivalent weight of sulfuric acid (H2SO4) = 49.03 g/equivalent of H+ I think I studied in the book like : Divide the molecular weight of an acid by the number of replaceable H atoms; Divide the molecular weight of a base by the number of OH groups; and Divide the molecular weight of a salt by the number of H's or OH's that reacted to form it. ..i.e Equivalent weight = molecular weight/valence ... For compounds like H2SO4, MgSo4, etc ... the valence =2 !! Is this what you are looking for ? @mathslover
I am like JFraser: I have never used equivalent weight. Normality can be useful. I sometimes use it for redox reactions. If you have the following half reaction: \(MnO_4^- +8H^++5e^-\rightleftharpoons Mn^{2+}+4H_2O\) then a 1 M solution of acidic permanganate ions will be considered 5 N because 1 mole of permanganate ions can accept 5 moles of electrons. The problem with normality is that a given compound can react according to different half equations when the other reactant changes, so a 1 M solution can be 5N with a reactant A and 3N with a reactant B. This is why we have limited to only a few well-chosen cases the use of this notation.
Thanks a lot for the help @Koikkara and @Vincent-Lyon.Fr !
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