In the diagram, DC is tangent to the circle, AC=12cm , and BD=2sqrt(34cm). Find AD

Question

anonymous · Answer

attachment

mikurout · Answer

Nearly 16 cm.

mathslover · Answer

@mikurout - Giving out answers is not allowed on OpenStudy. For more details , refer to 

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@ltp1212 - You're given with BD = $2\sqrt{34}$ and AC (diameter) = 12 cm

Since, radius is the half of diameter : 

So, radius ( BC ) = AC / 2 = ?

anonymous · Answer

@mathslover BC=6

mathslover · Answer

yes, right. Now, in Triangle BCD, you have : 

BC = 6 and BD = $2\sqrt{34}$ 

Use pythagoras theorem to find CD .

anonymous · Answer

do i simplify BD to 11.66?

mathslover · Answer

No.. 

When you will square it , the square root will automatically be removed :

Base ^2 + perpendicular ^2 = hypotenuse^2

Here you have base = CD 

Perpendicular = BC and Hypotenuse = BD

anonymous · Answer

$$x^{2}+6^2=136$$
$$x^2+36=136$$
$$x^2=100$$
$$x=10$$

anonymous · Answer

@mathslover thanks my answer is 10cm

mathslover · Answer

Perfect work. Its right. @ltp1212

mikurout · Answer

@ltp1212 But You have asked to find out AD .