Question

Never done a logarithmic graph?

Answer 1

@Isaiah.Feynman

Answer 2

do you mean 2^y=5x ?

Answer 3

ok
now put some y and find x

Answer 4

y=0 2^0=5x --->5x=1 --->x=1/5

y=1 2=5x ----> x=2/5

y=-1 1/2=5x ---> x/10

Answer 5

The fourth one.

Answer 6

or do like this
\[2^y=5x \\ \log_{2} 2^y=\log_{2}5x \\y=\log_{2}5x\\5x>0 \rightarrow x>0\\ \]

Answer 7

answer is not 4th

Answer 8

because when 5x=1 and y=0 x=0.2

Answer 9

answer is 3rd

Answer 10

Ahh I see.

Answer 11

what is right ?

Answer 12

if |r|<1
?

Answer 13

first problem was
"c"
yes

Answer 14

\[a1=4,a2=-8\\a1=4\\a2=a1*r=-8\\4(r)=-8\\r=-2\\an=a1*r^{n-1}\\so\\an=4(-2)^{n-1}\]

Answer 15

yes b