Question

what is an equation for the translation of (x-2)^2+(y+1)^2=16 by 5 units left and 4 units up?

a. (x-3)^2+(y+3)^2=16
b. (x+3)^2+(y+5)^2=16
c. (x-3)^2+(y-5)^2=16
d.(x+3)^2+(y-3)^2=16

Answer 1

what is an equation in standard form of an ellipse centered at the origin with the vertex (-6,0) and co-vertex (4,0)?

Answer 2

For your first question, I think that the answer would be B!
The way you would go about solving this problem is by realizing that the (x-2)^2 indicates a horizontal shift and the (y+1)^2 indicates a vertical shift. So, it says that the translation moves 5 units to the left, which means that you would add 5 to (-2) making it equal +3. Then, it says that it translates 4 units up, so then you would add 4 to (1) making it equal to (+5). So that is why the answer would be B (x+3)^2 + (y+5)^2=16.
:)


I don't know how to answer your other question though.

Answer 3

ah pre-calc, how boring i found it, gl chloey :)

Answer 4

._____. shh.