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Mathematics 7 Online
OpenStudy (anonymous):

Help PLEASE - if this is the graph of f(x)=a^(x+h) +k then .... (answers on the attachment along with graph)

OpenStudy (anonymous):

OpenStudy (anonymous):

ok with this one i have absolutely no idea what this means .... lol ANYONE .... help

OpenStudy (anonymous):

graphed it n_n

OpenStudy (anonymous):

OpenStudy (saifoo.khan):

now can you see that -10 tells us the y-displacement.

OpenStudy (saifoo.khan):

So if the graph comes down, k should be negative. Get this?

OpenStudy (anonymous):

yesss getting it n_n so k is y coordinate

OpenStudy (anonymous):

meaning up or down

OpenStudy (saifoo.khan):

Not the y-cordinate to be exact. But yes, the "y-change/movement/displacement.

OpenStudy (anonymous):

oh okkkkkkk then

OpenStudy (saifoo.khan):

Now try guessing the value of h.

OpenStudy (anonymous):

h would be the y-change, right?

OpenStudy (anonymous):

if so then around -3 to -4

OpenStudy (saifoo.khan):

h would be the change on the x-axis. Try drawing th e graph of 2^x and then compare.

OpenStudy (anonymous):

ok i guess h would be around 5 or 6 ... @saifoo.khan

OpenStudy (saifoo.khan):

Try again. Hint: Because of h > 0 (i.e. h = 5), the graph moved to the left side.

OpenStudy (anonymous):

would it be a Negative number then ?

OpenStudy (anonymous):

ohhhh would the answer to the question question be D h>0 and k<0 n_n - since k is -3 or -4 its less than zero??

OpenStudy (saifoo.khan):

No. http://assets.openstudy.com/updates/attachments/53993ea6e4b04b76852a7f45-meln_n-1402551983564-math3.png ^^ In this graph, the graph is moving to the RIGHT.

OpenStudy (anonymous):

ohhhhh my bad im getting the graphs mix LOL ---

OpenStudy (saifoo.khan):

;)

OpenStudy (anonymous):

im sorry im heading no where @saifoo.khan im really bad with math

OpenStudy (anonymous):

would the answer be A h<0 and k>0 ???

OpenStudy (saifoo.khan):

k is like -10 in this case. h is the opposite of 5 in 2^(x+5) - 10 problem.

OpenStudy (saifoo.khan):

Try reading the whole thread again. Don't rush.

OpenStudy (anonymous):

ok thank you i will defitinely go over it

OpenStudy (saifoo.khan):

Knock me if you still don't understand it. (:

OpenStudy (anonymous):

ok thank you n_n @saifoo.khan !

OpenStudy (anonymous):

hello im sorry to bother you again.... BUT i gave up lol i dont really know what im doing --- this is what i have -> k will be negative because its going down around -3 or -4 ...... h would be positive because the graph is going to the right and it looks like x would be 5 or 6 ----- other than that im at a Dead End :( i dont really know what i am suppose to look for ??? @saifoo.khan

OpenStudy (anonymous):

idk why but i always end up with answer D

OpenStudy (agent0smith):

That's all you need... why is the question still open...?

OpenStudy (saifoo.khan):

When: h - negative - right. h - positive - left. It's the opposite actually.

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

because i have come to no conclusion... @agent0smith

OpenStudy (saifoo.khan):

k is negative? Now just tell me where is your graph going? Left or right?

OpenStudy (anonymous):

right...

OpenStudy (saifoo.khan):

So h should be negative.

OpenStudy (anonymous):

ok so far then both k and h are negative ...

OpenStudy (anonymous):

meaning both would be less than zero

OpenStudy (saifoo.khan):

Yes, sir.

OpenStudy (anonymous):

ohhhh soooo its B n_n

OpenStudy (saifoo.khan):

Yes, sir.

OpenStudy (anonymous):

omgoshhhhhhhhh i am in great depth to you thank you n_n! @saifoo.khan

OpenStudy (saifoo.khan):

How deep?

OpenStudy (anonymous):

lol

OpenStudy (saifoo.khan):

;)

OpenStudy (agent0smith):

Oh yeah it is reversed here. Normally the equation uses x-h not x+h. When it's x-h, positive h means it goes right. Negative h means left. They messed with convention here.

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