help?
@agent0smith
According to ur figure square of distance from library to park is the product of distance from library to football field and distance from library to home. from this u can find the distance of library from park. After this using pythagorean theorem u can find out the distance between park and football field.
Geometric mean.
so the answer is the 1st option.
Or: http://www.cliffsnotes.com/math/geometry/right-triangles/altitude-to-the-hypotenuse
A: Let the distance between park and library be X units, hence using geometric mean property we have; \[\huge X^2 = 12 \times 9\] \[\huge \rightarrow X = \sqrt{12 } \times \sqrt 9\] \[\huge \rightarrow X = 2\sqrt{3 } \times 3 = 6\sqrt{3 }\] \[\huge \rightarrow X = 6\sqrt{3 }\] Hence library is 6√3 miles from the park. B: Now let us consider the right triangle formed by the vertices park, library and football field Let the distance from park to football field be Y miles, hence by Pythagoras theorem we have; \[\huge Y^2= 12^2 + (6\sqrt3)^2\] \[\huge \rightarrow Y^2= 144 + 36 \times 3\] \[\huge \rightarrow Y^2= 144 + 108=252\] \[\huge \rightarrow Y^2=252\] \[\huge \rightarrow Y=\sqrt{252}\] \[\huge \rightarrow Y=\sqrt{36 \times 7}\] \[\huge \rightarrow Y=6\sqrt{7}\] Hence the distance from park to football field is 6√7miles thus first option is the correct answer. @abbie
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