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Mathematics 9 Online
OpenStudy (anonymous):

4x^3 + 12x^2 - 14x + 8 divided by x + 4?

OpenStudy (anonymous):

Factor the top, so you get 2(x+4)(2x^2-2x+1)

OpenStudy (anonymous):

so something like 4x^2 + 4x -2x?

OpenStudy (isaiah.feynman):

Wouldn't synthetic division be useful here?

OpenStudy (anonymous):

Once you factor the top (I already did for you) \[\frac{ 4x^3+12x^2-14x+8 }{ x+4 } \implies \frac{ 2(x+4)(2x^2-2x+1) }{ (x+4) }\] \[2(2x^2-2x+1) \] we cancelled the (x+4)

OpenStudy (anonymous):

so 4x^2 - 4x + 2?

OpenStudy (isaiah.feynman):

Yes.

OpenStudy (anonymous):

Sure, I have no clue what your question is exactly asking, but you can leave it as that.

OpenStudy (anonymous):

haha it was asking for the quotient

OpenStudy (isaiah.feynman):

Then we leave it as that.

OpenStudy (anonymous):

Thanks

OpenStudy (isaiah.feynman):

Thank the bat.

OpenStudy (anonymous):

hahaahaha

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