Question

three capacitors of capacitances 6meuF each are available.the minimum and the maximum capacitances ,which may be obtained are
a 6,18
b 3,12
c 2,12
d 2,18

Answer 1

Hello @fruits !

\(\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\sf\color{blue}{~~~~Welcome~to~OpenStudy!~\ddot\smile}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\)

Answer 2

Minimum will be when we group the three capacitances into series combo. so the min will be 2 and max will be when we group them in parallel, so max will be 18

Answer 3

In series combo \[\frac{ 1 }{ Cf }=\frac{ 1 }{ C1 }+\frac{ 1 }{ C2 }+ .......\]

Answer 4

In parallel combo, \[C_{f}=C_{1}+C_{2}+......\]

Answer 5

ok thank you

Answer 6

\(\Huge\text{Anytime !}\)
\(\huge\ddot\smile\)

Answer 7

can i know in which standard u are in now??

Answer 8

http://openstudy.com/users/abhisar
Here u will find all the info

Answer 9

\(\color{green}{\huge\ddot\smile}\)

Answer 10

ohh so great:D

Answer 11

u too
\(\color{green}{\huge\ddot\smile}\)

Answer 12

M still in 12th

Answer 13

That's also not easy :D

Answer 14

hmm u r right:d

Answer 15

All the best for ur Future !
\(\color{green}{\huge\ddot\smile}\)

Answer 16

thanx