What is the angle of refraction when a ray of light passes from ethanol to air if the incident angle is 34°? The refractive index of ethanol is 1.36 and of air is 1.00.

Question

ipwnbunnies · Answer

Use Snell's Law.
$$n_1 \sin(\Theta_{1}) = n_2 \sin(\Theta_{2})$$
Where the left side of the equation is the incident refractive index and angle. The right is the...errr...transmitted info.

ipwnbunnies · Answer

So, it's going from ethanol to air.
n1 = 1.36
n2 = 1.00

anonymous · Answer

I don't understand any of that ah

anonymous · Answer

1.36sin(Θ1)=1.00sin(Θ2) but how do i find (Θ1) and (Θ2)

anonymous · Answer

and like
i dunno

ipwnbunnies · Answer

Θ1 is the incident angle, 34 degrees.
$$(1.36)\sin(34 \deg) = (1.00)\sin (\Theta_2)$$
I suggest to solve the left side first, use a calculator. Divide by 1, to get sin(Θ2) by itself.
Finally, use inverse sine.

anonymous · Answer

i got 0.719

ipwnbunnies · Answer

For the left side?

anonymous · Answer

yeah

ipwnbunnies · Answer

I got something a little different. o-o

anonymous · Answer

i don't know how to do reverse sine i have no idea what i am doing

ipwnbunnies · Answer

I got 0.760. And don't you know how to use a calculator?
$$0.760 = \sin(\Theta_2)$$
$$\Theta_2 = \sin^{-1}(0.760)$$

ipwnbunnies · Answer

Do you have your calculator? Press 2nd Key -> SIN. That should be the inverse sine function.

shannonmcc10 · Answer

Answer is 49 degrees