Question

11.3 mL sample of CH3OH - P(density) = 0.793 g/mL is dissolved in enough water to produce 75.0 mL of solution with P(0.980) g/mL.
SOLVE for %mass, %volume, mole fraction, molarity and molality.
pls help.

Answer 1

Hello @ulahlynn !

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Answer 2

Lets first c Molarity

Answer 3

U know the formula for it ?

Answer 4

:) thanks.
and yeah its moles of solute / L of solution

Answer 5

Chk this xplanation
http://openstudy.com/study#/updates/5399654ae4b068926b38d481

Answer 6

ok.. thank you soo much... ill just solve it now.. and can you please check my answer?. :)

Answer 7

Since density of CH3OH is 0.793, 11.3 ml of CH3OH will contain 0.793 X 11.3 = 8.96 g. Now solve as per the xplanation given

Answer 8

Yeahh sure i'll do that

Answer 9

sorry for the delay.. but is the answer 3.98 M?

Answer 10

Recheck it will be apprx 1.6 M

Answer 11

u got upto 8.96 g

Answer 12

??

Answer 13

no u r ryt, its apprx 3.75 M

Answer 14

ohh... what i did is 8.96 g / 30 g of ch3oh = 0.299 and 0.299/0.075L of solution and 3.98M is what i got.. is this wrong??

Answer 15

\(\color{green}{\huge\ddot\smile}\)

Answer 16

ohh.. THANKS. can you help me with the other problems?

Answer 17

SUre...but it will take time..since i have so many pending request

Answer 18

oh. sorry. just answer those pending requests .. ill just type in my answers.
can you just atleast check them if its alright ? :)

Answer 19

You have a molarity, which pieces do you still need?

Answer 20

the %mass.

Answer 21

sorry for the late reply @JFraser ... I didn't notice it.

Answer 22

yes i can do that

Answer 23

Any percent is always the ratio of one piece of the mixture to the whole mixture. Since you need mass%, you need to find the mass of the alcohol that was added, and the mass of the total solution. The goo news is that you're given the VOLUME of each and the DENSITY of each