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Mathematics 10 Online
OpenStudy (epoweritheta):

please help me to understand independent events in probability

OpenStudy (perl):

A and B are said to be independent, if the occurrence of event A does not affect the probability of event B. Knowing that A has already occurred does not affect probability of B. The classic example is drawing cards with replacement and without replacement. if I ask you, what is probability of drawing two ace's from a 52 card deck, two different cases. with replacement : without replacement:

OpenStudy (perl):

ok so far?

OpenStudy (perl):

Probability ( draw two aces with replacement) = 4/52 * 4/52 Probability ( draw 2 aces without replacement) = 4/52 * 3/51

OpenStudy (epoweritheta):

ya... i understand ... , so does event A have to occur first then event B ??

OpenStudy (perl):

in this example, yes it is assumed. maybe i can do an easier example. if you throw two dice, the probability of getting 3 on both throws. A = getting 3 on first throw B = getting 3 on second throw. B is independent of A , since if A occured (you got a 3 on first throw), it doesnt affect probability of getting a 3 on second throw of die

OpenStudy (epoweritheta):

ya..but this example see find the probabilty of choosing a red face card from a deck of card ?? is = P(choosing red card) *P(choosing face card ) how r those two events independent ?

OpenStudy (perl):

if P(B |A ) = P(B) , then we say B is 'independent' of A P(B | A ) means probability of B *given* that you know A has occurred. P(B) means probability of B where you don't know if A has or has not occurred (unconditional probability)

OpenStudy (perl):

the example has to say whether you are replacing the card or not, back to the deck

OpenStudy (epoweritheta):

ur taking only 1 card there a red-face card

OpenStudy (perl):

for just one card, it doesnt make sense to say independent. usually you need two events

OpenStudy (perl):

some event is independent of another event. the statement is a relational statement, like x is taller than y , A is independent of B . you need two things to discuss independence

OpenStudy (epoweritheta):

oh...

OpenStudy (perl):

in your example, P ( choosing red face card ) is just the probability of choosing one red face card. there is no independence in this event by itself

OpenStudy (perl):

but if you said, find probability of drawing two red face cards, which is equal to the probability of drawing one red face card *followed* by drawing another red face card... then the events would be independent or dependent based on whether you are drawing with or without replacement

OpenStudy (epoweritheta):

thank you :)

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