Question

The pressure in an engine cylinder increases from 7.6 atm to 13 atm as the gas is compressed from 0.50 L to 0.10 L. What is the expected cylinder temperature if the gas was initially 15°C?

Answer 1

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Answer 2

@Somy

Answer 3

oh dear im pretty sure @Abhisar u know it lol

Answer 4

is it -174.47 C

Answer 5

wait

Answer 6

ohkay

Answer 7

i love SI system so im gonna do it that way

Answer 8

No that's wrong

Answer 9

ohkay

Answer 10

Its 985.26 K i think

Answer 11

im getting approximately 569 Celsius

Answer 12

oh wait i did it opposite way round lol

Answer 13

ur first answer is right tho

Answer 14

-174.47

Answer 15

yes second one will be ryt

Answer 16

Thankyou @Somy !

Answer 17

\[ \frac{ P _{1} V _{1} }{ T _{1} } = \frac{ P _{2} V _{2} }{ T _{2} }\]

\[\frac{ 7.6 \times 0.50 }{ 15+273 } =\frac{ 13\times 0.10 }{ T _{2} }\]

\[T _{2}= \frac{ (13\times 0.10)\times(15+273) }{ 7.6\times0.50 }\]
\[T _{2}= 98.5 K\]
\[T _{2}= 98.5 K - 273= -174.5 °C \]

Answer 18

u r welcome @Abhisar :*

Answer 19

thank you!

Answer 20

u r welcome :)