Question

Find the amplitude and the period of b(x) = -5sin(πx).

Answer 1

amplitude and period of a function like
\[y=asin(bx)\] is
amplitude=a
period=\[2(\pi)/b\]

Answer 2

okay well i'm still confused

Answer 3

okay In general, if we have y = Asin(Bx - C) then,

amplitude is A

period is 2π/B

phase shift C/B
here the function is of the form y=A sin(Bx)...................(1)
and ur function is y=-5sin(pi*x)
compare it with equation (1) and u'll get A=-5 which is the amplitude
and period=\[2\pi/B=2\pi/\pi=2\]

Answer 4

ok then??

Answer 5

ohh okay i see now thank you