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Mathematics 7 Online
OpenStudy (lovelyharmonics):

dot product

OpenStudy (lovelyharmonics):

Find the first six terms of the sequence. a1 = -1, an = 2 • an-1

OpenStudy (lovelyharmonics):

hi again c:

OpenStudy (anonymous):

oh hi. SOrry idk this one :(

OpenStudy (anonymous):

this might help http://www.mathsisfun.com/algebra/vectors-dot-product.html

OpenStudy (lovelyharmonics):

that link just took a problem and exploded it bro....

OpenStudy (anonymous):

This doesn't look like it has anything to do with dot products. You're given the definition for a recursive sequence. The dot you see is just multiplication; each successive term of the sequence is twice the preceding term.

OpenStudy (lovelyharmonics):

oh makes sense now so i just multiply those two and get -2?

OpenStudy (anonymous):

how you get dot product in here anyways? :)

OpenStudy (anonymous):

Right, since \(a_1=-1\) and \(a_n=2a_{n-1}\), that means \(a_2=2a_1=-2\). Keep up with the pattern and you'll get your first six terms.

OpenStudy (lovelyharmonics):

idk.... it was a dot..... and woah .-. can i just multiply it by 2 every time?

OpenStudy (anonymous):

nope you get a new value each time

OpenStudy (anonymous):

Yes, that's what the sequence is. \(a_3=2a_2=2(-2)=-4\) and so on.

OpenStudy (anonymous):

a1 = -1, an = 2 • an-1 a1=-1 is first a2=2*(a1)= -2 2nd -1 a3=2*(a2)= -4 3rd -2 amd so on however there should be a formula

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