Find the sum of the geometric sequence. 1, one divided by four, one divided by sixteen, one divided by sixty four, one divided by two hundred and fifty six
1/4 +1/16 +1/64 these terms are in 4's power
can you tell me whats the common ratio
honestly i dont know
to find the common ratio, take the second term and divide it by the first term. (1/16) / (1/4 = 1/16 * 4/1 = 4/16 = 1/4 so the common ratio is 1/4. Is this all the numbers ? Is there only 4 numbers that are trying to find the sum of ?
there 5 number 1, 1/4 ,1/16, 1/64 , 1/256
oh...1 is the first term ?
yes
so
yes still the same ratio
so what is the the sum of the geometric sequence.
you cant make bricks without clay,you cant make buildings without bricks data data! how can you find something without data
you have the ratio now now formula is a(1-r^n/1-r)
first term is 1 r= 1/4
and n is 5
so sum will be (1-1/256)/1-1/4
so 255/4 *4/3 = 255/3 = 85
thats ur sum
341/256 is the answer. I just took the test and got it right.
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