Question

For the graphed function f(x) = −(5)x − 3 + 2, calculate the average rate of change from x = 4 to x = 6.

Answer 1

the rate of change is -10

Answer 2

These are my options −68

−60

68

60

Answer 3

I hope this helps!

Answer 4

I dont have either of those answers

Answer 5

@thedornob @EricaKalmeta

Answer 6

Well what I did was substitute the two x values it gives you to find, and when I subbed 4 in for x, I got -21, and when I subbed 6 for x, I got -31. So its a -10 change

Answer 7

here is a graph http://gyazo.com/5e3cf18c0419e3785e8f4a6124945666 that was with it

Answer 8

I don't know if that will help

Answer 9

What class is this for?

Answer 10

Algebra 2

Answer 11

The graphed function is

\[\large f(x) = -5x - 3 + 2\]

correct? or is that 'x' an exponent?

Answer 12

Regardless....the formula we can use (since this is Algebra 2) would be

\[\large \frac{f(b) - f(a)}{b - a}\]

Meaning...with the interval we are given (from x = 4 to x = 6)

a = 4
b = 6

So we have

\[\large \frac{f(b) - f(a)}{6 - 4}\]

Now we just need to see what the function you were given, equals when you plug 'x' = 6 and x = 4 into it

And from what I'm coming up with for results...I believe that we have an exponent here...what part of the equation that you gave is an exponent?

Answer 13

I think I found it out...I believe your equation SHOULD look like

\[\large f(x) = -(5)^{x - 3} + 2\]

So when we plug in x = 6 we have

\[\large f(b) = -(5)^{3} + 2 = -125 + 2 = -123\]
And when we pug in x = 4 we have
\[\large f(a) = -(5)^{1} + 2 = -5 + 2 = -3\]

So that means

\[\large \frac{-123 - (-3)}{6 - 4} = \frac{-120}{2} = -60\]

Answer 14

oh im sorry I kept losing connection yes its an exponent thank you very much!