if cos theta =-4/7 what are the values of sin theta and tan theta
i did it halfway through but stuck at the fraction part
What method are you trying to use?
sin 2 theta + cos 2 theta = 1
So, you have: \[\sin^2(\theta) + (\frac{4}{7})^2=1?\] What is \[(\frac{4}{7})^2\]
yes and then i got sin 2 theta + 16/49
I subtract on both sides but i dont know how to subtract fraction from whole
Here's a clue: \[1=\frac{49}{49}\]
hmmmm
1/49?
ive never seen that b4 lol
\[\frac{49}{49} - \frac{16}{49} = \frac{49-16}{49}\]
So, \[\sin^2(\theta) = \frac{33}{49} \rightarrow \sin(\theta) = \frac{\sqrt{33}}{\sqrt{49}} = \frac{\sqrt{33}}{7}\]
Ohh okay I see! Ok Ill tell u wat my final answer is
sin theta will be sine theta =+/- sqrt 33/7
can u help with one more. Its very confusin
@ddcamp
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