Let log[b] A=1, log[b] C=3, log[b] D=4
What is the value of log[b] (A^5 C^2/D^6)

Im confused can someone explain how to do this?

A. 26
B. 0
C. There isn't enough information to answer the question.
D. -13

How is -13 the answer ????

Question

Let log[b] A=1, log[b] C=3, log[b] D=4 
What is the value of log[b] (A^5 C^2/D^6)

Im confused can someone explain how to do this?

A. 26
B. 0
C. There isn't enough information to answer the question.
D. -13

How is -13 the answer ????

anonymous · Answer

$$5\log _{b}A  + 2\log _{b}C- 6\log _{b}D$$

amistre64 · Answer

seems fair

anonymous · Answer

but how would it become -13?

amistre64 · Answer

$$5\log _{b}A  + 2\log _{b}C- 6\log _{b}D$$
but they tell you the log parts, sub them in
$$5(1)+ 2(3)- 6(4)$$

anonymous · Answer

ohhhhhhhhhhhhhhhh! 5+6-24 = -13 !!!! ohhhhh thank youuuu @amistre64

amistre64 · Answer

:)  yep

anonymous · Answer

i didnt see that lol i was confuse cuz 5+2-6 was definitely not -13 thank you @amistre64