Question

A quadratic equation is shown below:

3x^2 - 16x + 2 = 0

Part A: Describe the solution(s) to the equation by just determining the discriminant. Show your work. (3 points)

Part B: Solve 9x^2 + 3x - 2 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points)

Part C: Solve 3x^2 - 10x + 2 = 0 by using a method different from the one you used in Part B. Show the steps of your work. (3 points)

Answer 1

@YanaSidlinskiy

Answer 2

@Data_LG2

Answer 3

Quadratic Formula:
\[ax^2+bx+c\]

Answer 4

i showed you the formulas that you can use.

For part A, you are looking for the discriminant.
For parts B and C, you can use the quadratic formula.

http://openstudy.com/users/data_lg2#/updates/539a2d8ce4b0eb8de56c8c48

Answer 5

How do you find the discriminant? Could I use like mathway.com?

Answer 6

so in your case, \(a=3,\ b=-16,\ c=2\) plug this values into the formula

Answer 7

and thats for part a?

Answer 8

@YanaSidlinskiy \(ax^2 + bx +c=0\) is Not the quadratic formula, it is the standard form of a quadratic equation.

@ksander yes

Answer 9

*ksaunders

Answer 10

My bad..Sorry 'bout that...

Answer 11

no worries ;)

Answer 12

okay so for Part A the answer is .. -280?

Answer 13

can you show me your solution? i got a different answer

Answer 14

oops sorry wrong one

Answer 15

nope, remember that "-tive" sign should be INSIDE the bracket, because you are squaring the value of b:
\((-16)^2-4(3)(2)\)=?

If the discriminant is positive, then the equation will have two solutions
if the discriminant is equal to zero, there is only one solution
if the discriminant is negative, then there is no solution.

Answer 16

so like this

Answer 17

yes. So based from your answer, how many solution(s) does the equation have?

Answer 18

two

Answer 19

right :) so you're done with part A.

try doing Part B, using the quadratic formula

Answer 20

Even though you use an online software, you still have to show your solution because it says on your question. Also, if you will try it on your own, you can learn it better. I'm not saying that you should not use it, but use it only to check if your answer is right :)

Goodluck! I have to go, see ya later ;)

Answer 21

okay(: thank you so much!