Question

divide. (10d^9-6d^8+4d^5)/(2d^3)
PLEASE HELP

Answer 1

@Isaiah.Feynman

Answer 2

@triciaal

Answer 3

Hint: divide each term of the numerator by the denominator.

Answer 4

ok

Answer 5

and remember that when you divide numbers or letters with the same base you subtract the powers

Answer 6

example d^5 / d^2 = d^(5-2) =d^3

Answer 7

\(\bf \cfrac{10d^9-6d^8+4d^5}{2d^3}\implies \cfrac{10d^9}{2d^3}-\cfrac{6d^8}{2d^3}+\cfrac{4d^5}{2d^3}
\\ \quad \\
\cfrac{\cancel{ 10d^3 }d^6}{\cancel{ 2d^3 }}-\cfrac{\cancel{ 6d^3 }d^5}{\cancel{ 2d^3 }}+\cfrac{\cancel{ 4d^3 }d^2}{\cancel{ 2d^3 }}\)

Answer 8

forgot your numbers

Answer 9

@jdoe0001 forgot the numbers 10/2 etc

Answer 10

wait so would it b 5d^9-3d^9+2d^5 ? @triciaal

Answer 11

5d^6 - 3d^5+ 2d^2

Answer 12

are u good at algebra 1B?

Answer 13

hope so yes

Answer 14

can u message me back @triciaal