Mark is in a deep hole looking for treasure. He is standing 10 feet below the surface. He throws an old shoe he found with an initial upward velocity of 36 ft/sec. How long until it lands outside the hole, having gone up and back down? Use the formula, where h is the height of the shoe in feet (relative to the surface) and t is the time in seconds since Mark threw it. Ignore air resistance and round your answer to the nearest tenth.
A.
0.3 seconds
B.
1.9 seconds
C.
2.1 seconds
D.
It will not make it outside the hole.

Question

anonymous · Answer

Well if the shoe is thrown straight up into the air, that means that we have motion in only one dimension, the vertical dimension, or along the y-axis. That means there will be no horizontal motion.