List all the values that satisfy (x,-sqrt3/2)
usually I get 4 points right and the last one wrong
Okay, so the graph is of the sine wave. An ordered pair on this graph would be an x value, or the input, and a y value, or the function output. Within the given range of x values (the interval in your question), which of these x values makes \[\sin (x)=-\sqrt{3}/2\]There is a finite amount since you are within a range.
Its looking for 5 points I think this should be the first four but i do not know the 5. 5pi3, 4pi/3,-2pi/3, -pi/3
What you should do is decide whether or not the terminal angle which solves this problem lies within the given range. If it does, include that one and then start subtracting 2*pi from the angle as many times as you can and still be within the given range.
Hint: the terminal angle, \[4\pi /3\]is within the given range.
So I add 2pi to 4pi/3?
Subtract. Adding it goes above your max range. You can tell this by putting the values into common denominators.
is this right
There is an easy way to check. First, see if you're smallest value is within the range. We already know that your largest value is within the range (because I told you). So if we already know that any angle x plus or minus 2*pi has the same trig value as the original angle x, and all your proposed solutions do indeed fall within the range, we should be able to reasonably assume that they are the answers we are looking for. Maybe not so easy. lol it depends on your relative definition of hard.
To check whether or not a value is within the range, make it so that the value you are checking at the end values of your range have the same denominator. This makes it obvious if it does or does not lie within the range.
hmm it came up wrong ):
As in the computer says those answers are wrong?
yea its online hw
Oh, I just noticed that the low end of your interval has a denominator of 6, not 3.
wait what u mean all my denominators r 3?
Your bottom interval is \[-23\pi /6\]NOT \[-23\pi/3\] That means that maybe not all of your proposed solutions fall within your interval. Multiply all your solutions by \[2/2\]and you will see more clearly what I am referring to.
ok ok thanks!
No problem. Feel free to ask me about any other questions you may have.
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