Question

Why is (6, –2) not a solution to the system of equations given?
2x-3y= 18
5x=3y=3

Answer 1

Is your 2nd equation correct?
5x = 3y = 3

Answer 2

if it is, then it's because that second equation would simplify to y=1 and x=3/5 and x=/=y so it all doesnt work. but i suspect one of those should be subtraction

Answer 3

I bet it is 5x + 3y = 3, since the + and the = are on the same key.

Answer 4

oooh good guess

Answer 5

Why is (6, –2) not a solution to the system of equations given?
2x-3y= 18
5x+3y=3

Answer 6

So, if you were to graph the lines, what would the "solution" look like on the graph?

Answer 7

alternately, plug in the values x=6 and y=-2 into the second equation and see if its a valid solution

Answer 8

Yes, the "solution" to a system of linear equations (or any other system) is the point (or points) that the graphs of the functions have in common. In other words, the points where they intersect.

Answer 9

And, as LifeEngineer pointed out, it can be verified algebraically by substituting the values for x and y into the equations to see if they "work" in both equations.

Answer 10

Guys I'm calling it a night. good night and god bless

Answer 11

So 2x - 3y = 18 ---> 2(6) - 3(-2) = 12 + 6 = 18

(so (6,-2) works in that equation)

and

5x + 3y = 3 ---> 5(6) + 3(-2) = 30 - 6 = 24

(so, since 3 isn't equal to 24, the point (6, -2) doesn't appear to work in that equation.)

Answer 12

Have a good night! :D

Answer 13

You too, LifeEngineer. :)

Answer 14

Good night to all :D