Question

hyperbolas

Answer 1

Find an equation in standard form for the hyperbola with vertices at (0, ±6) and foci at (0, ±9).

Answer 2

do you just square these to find the denominators?

Answer 3

nope

Answer 4

hmm
you have to find b and a right
so verices are (0,+-6)
so b=6

Answer 5

okay so then i square that and its 36

Answer 6

your foci is (0,+-9)
a will be
\[\sqrt{6^2 - a^2} =9\]

Answer 7

thats + underroot *
typo

Answer 8

\[\frac{ y^2 }{ 36 } - \frac{ x^2 }{ 81 }\]

Answer 9

so a^2 = 81-36
a^2 = 45

Answer 10

x^2/45

Answer 11

so y^2/36 - x^2/45

Answer 12

=1

Answer 13

i have a few more questions im going to post if you would like to help c:

Answer 14

yeah okay